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6(m^2)+24m+18=0
a = 6; b = 24; c = +18;
Δ = b2-4ac
Δ = 242-4·6·18
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{144}=12$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-12}{2*6}=\frac{-36}{12} =-3 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+12}{2*6}=\frac{-12}{12} =-1 $
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